Return Only Most Recent Entry Per Id
Solution 1:
When faced with multiple results from a join and you want to match the most recently dated row, a correlated subquery in the join criteria is one I have found to be quite simple to write and quite fast in execution:
...
JOIN aktivitaet a
ON a.bold_id = al.aktivitaeten
AND a.creationdatetime =(
SELECTMax( creationdatetime )
FROM aktivitaet
WHERE bold_id = a.bold_id )
...
Solution 2:
Quoting the MySQL manual (though it's valid for all DBMS implementing the SQL '92 Standard):
The Rows Holding the Group-wise Maximum of a Certain Column
Task: For each article, find the dealer or dealers with the most expensive price.
This problem can be solved with a subquery like this one:
SELECT article, dealer, price
FROM shop s1
WHERE price=(SELECTMAX(s2.price)
FROM shop s2
WHERE s1.article = s2.article);
+---------+--------+-------+| article | dealer | price |+---------+--------+-------+|0001| B |3.99||0002| A |10.99||0003| C |1.69||0004| D |19.95|+---------+--------+-------+The preceding example uses a correlated subquery, which can be inefficient (see Section 13.2.10.7, “Correlated Subqueries”). Other possibilities for solving the problem are to use an uncorrelated subquery in the FROM clause or a LEFT JOIN.
Uncorrelated subquery:
SELECT s1.article, dealer, s1.price
FROM shop s1
JOIN (
SELECT article, MAX(price) AS price
FROM shop
GROUPBY article) AS s2
ON s1.article = s2.article AND s1.price = s2.price;
LEFT JOIN:
SELECT s1.article, s1.dealer, s1.price
FROM shop s1
LEFTJOIN shop s2 ON s1.article = s2.article AND s1.price < s2.price
WHERE s2.article ISNULL;
The LEFT JOIN works on the basis that when s1.price is at its maximum value, there is no s2.price with a greater value and the s2 rows values will be NULL.
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