Php: How To Prevent Sql Injection From $_post
i have some php script and i think this have a lot of mistake. because of my limited knowledge in concatenation and SQL injection. At 1st time i'm not have any trouble because this
Solution 1:
Looks as if it could run, so if it fails please describe how.
There is, however, one immediately visible mistake in it: In the lines
$sQuery = "SELECT COUNT(*) FROM (SELECT LINE_NAME, MODEL_ONLY, VER_ONLY, PROD_NO,
LOT_SIZE, START_SERIAL, SERIAL_NO_LOW, SERIAL_NO_UP, PROD_DATE
FROM DOC_TO'.$sWhere.$sOrder.$sLimit.')";
you are starting a string with double quotes and you try to interrupt the string with single quotes, which will not work. So the code must be:
$sQuery = "SELECT COUNT(*) FROM (SELECT LINE_NAME, MODEL_ONLY, VER_ONLY, PROD_NO,
LOT_SIZE, START_SERIAL, SERIAL_NO_LOW, SERIAL_NO_UP, PROD_DATE
FROM DOC_TO".$sWhere.$sOrder.$sLimit.")";
Depending on your environment in addition there is an important security flaw in your code: For example in the line
$sLimit = " FIRST ".$_POST['iDisplayStart']." SKIP ".$_POST['iDisplayLength'];
you are using $_POST to put it directly into an SQL query, which opens a so-called SQL injection security hole.
Solution 2:
i have found the answer from AndreKR's guidance:
$sLimit = "";
if ( isset( $_POST['iDisplayStart'] ) )
{
settype($iDisplayStart,'integer');
$iDisplayStart = $_POST['iDisplayStart'];
$iDisplayLength = $_POST['iDisplayLength'];
$sLimit = sprintf(" FIRST ".$iDisplayStart." SKIP ".$iDisplayLength);
}
and change all $_POST:
'%".$_POST['sSearch_0']."%'into''%".$_POST['sSearch_0']."%''//this to prevent injection For databases Like Oracle, DB2, MS SQL, Firebirdand change :
$sQuery = "SELECT COUNT(*) FROM(......)
into
$sQuery = "SELECT COUNT(*) AS DCOUNT FROM DOC_TO".$sWhere.$sLimit.";"; //delete $sOrder$aResultFilterTotal = ibase_fetch_assoc($rResultFilterTotal);
$iFilteredTotal = $aResultFilterTotal['DCOUNT']; //change from ......[0]
and add at the last php page:
ibase_free_result($aResultTotal);
?>
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