In Oracle, In Regards To Syntax - How Do I Convert The (+) Syntax To Modern Conventional Join?
Suppose I have a FROM clause like so : FROM apps.po_requisition_lines_all prl, apps.po_requisition_headers_all prha, po.po_req_distributions_all prda,
Solution 1:
Without seeing the schema, I find it difficult but this should set you in the right direction:
FROM apps.po_requisition_lines_all prl
INNERJOIN apps.po_requisition_headers_all prha ON prl.requisition_header_id = prha.requisition_header_id
INNERJOIN po.po_req_distributions_all prda ON prda.requisition_line_id = prl.requisition_line_id
LEFTJOIN po.po_distributions_all pda ON prda.distribution_id = pda.req_distribution_id
-- I note from the example provided that this is a right join-- Without seeing the schema, it looks to me as though it should be left-- As I say say, without seeing the schema, I probably shouldn't pass commentRIGHTJOIN po.po_headers_all pha ON pha.po_header_id = pda.po_header_id;
For an INNER JOIN you can just say JOIN although I think that explicitly saying INNER aids readability. I also note the example provided has WHERE 1=1 which is redundant.
Solution 2:
The + is old version of Outer Joins, and it differs where the + comes after equality sign or before it, But now it's recommended to use Join keywords instead of +, about the + sign if it comes:
After =:
select * from t1, t2
where t1.id=t2.id(+)
This means Left Outer Join:
select*from t1
leftouterjoin t2 on t1.id=t2.id
Before =:
select * from t1, t2
where t1.id(+)=t2.id
This means Right Outer Join:
select*from t1
Rightouterjoin t2 on t1.id=t2.id
Without +:
select * from t1, t2
where t1.id=t2.id
This means Inner Join:
select * from t1
join t2 on t1.id=t2.id
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