PIVOT Oracle - Transform Multiple Row Data To Single Row With Multiple Columns, No Aggregate Data

I have a need to transfer the following data set: in which only the highlighted lines are the one of interest (Tag in ('LN','SN')) as I am only interested in SerialNumber and LotN

Solution 1:

You aren't doing anything with the description, which also varies with the tag. It isn't aggregated so it in the implicit 'group by', so you get separate rows in the result set.

You can either capture that too with another (dummy) aggregate:

select * from (
  select * from TEST2 where tag in ('LN', 'SN')
)
PIVOT
(
  max(value) as value, max(description) as description
  for tag in ('LN' as ln, 'SN' as sn)
)
order by category, subcat, item, "Date";

Date      SUBCAT CATEGOR IT LN_VALUE          LN_DESCRIPTION  SN_VALUE          SN_DESCRIPTION
--------- ------ ------- -- ----------------- --------------- ----------------- ---------------
24-OCT-13 290223 1219576 25 1105618           Lot Number      3x12mm            Serial Number  
24-OCT-13 290223 1219576 28 1303757           Lot Number                                       
18-JUN-15 354506 1219576 4  1403114           Lot Number                                       
18-JUN-15 354506 1219576 9  7777777777        Lot Number      9.999999999999E12 Serial Number  

Or more likely exclude it from the intermediate result set if you don't want it, by specify the columns you do want instead of using *:

select * from (
  select category, subcat, item, "Date", tag, value
  from TEST2 where tag in ('LN', 'SN')
)
PIVOT
(
  max(value) for tag in ('LN' as ln, 'SN' as sn)
)
order by category, subcat, item, "Date";

CATEGOR SUBCAT IT Date      LN                SN              
------- ------ -- --------- ----------------- -----------------
1219576 290223 25 24-OCT-13 1105618           3x12mm           
1219576 290223 28 24-OCT-13 1303757                            
1219576 354506 4  18-JUN-15 1403114                            
1219576 354506 9  18-JUN-15 7777777777        9.999999999999E12

Solution 2:

Get table data in pivot xml

with a as (select to_char(xmltype.getclobval(JOB_XML))  k  from (
select * from (select ename,job from emp)

pivot xml ( max(ename) for job in (select job from emp))))

SELECT EXTRACTVALUE(VALUE(xml_list), '//column[1]') AS interface_no
      ,EXTRACTVALUE(VALUE(xml_list), '//column[2]') AS interface_name_a
  FROM TABLE(XMLSEQUENCE(EXTRACT(XMLType('<?xml version="1.0" encoding="UTF-8"?>'||(select * from a) ), 'PivotSet/item'))) xml_list;