MySQL INNER JOIN Of 3 Tables With Count And Totals
Solution 1:
Since the orders are linked to the companies via the customers, I don't think you need to perform two separate subqueries and join them; rather, I think you can just write:
SELECT companies.company AS "Company",
IFNULL(COUNT(DISTINCT companies_customers.customer_id), 0) AS "Total Customers",
IFNULL(SUM(orders.amount), 0) AS "All Orders Total"
FROM companies
LEFT
JOIN companies_customers
ON companies_customers.company_id = companies.id
LEFT
JOIN orders
ON orders.customer_id = companies_customers.customer_id
GROUP
BY companies.id
;
Edited to add: That said, I have to say that the schema doesn't really make sense to me. You have a many-to-many relationship between customers and companies — so, for example, John Smith is a customer of Acme Widget Company and of Intrepid Inc. — but then orders are just a property of the customer, not of the company. This means that if an order belongs to John Smith, then it necessarily belongs both to Acme Widget Company and to Intrepid Inc.. I don't think that can be right. Instead of having a customer_id field, I think orders needs to have a companies_customers_id field.
Solution 2:
I have 3 table that to keep team,tournament_round AND score_team_member about competition TEAM_A Vs TEAM_B ,multiple of round.(1,2,3...n) and multiple of members of team there is score by oneself.This code above are useful very much.
SELECT team.name AS "TEAM",team.id,
IFNULL(COUNT(DISTINCT `tournament_round`.id), 0) AS "TotalWin",
IFNULL(SUM(`score_team_member`.`score`)/(select count(*) from `team_member`where team_id=team.id group by team_id ), 0) AS "ScoreofTeam"
FROM `team`
LEFT
JOIN `tournament_round`
ON `tournament_round`.team_winner_id = `team`.id
LEFT
JOIN `score_team_member`
ON `score_team_member`.team_id = `team`.id
WHERE `team`.thematch_id='6' AND `team`.`category1`='MEP'
GROUP BY `team`.id ORDER by `TotalWin`DESC ,`ScoreofTeam` DESC
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